If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9a^2-36a=0
a = 9; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·9·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*9}=\frac{0}{18} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*9}=\frac{72}{18} =4 $
| t^2+20T+57=0 | | 4(-5y+4)=-76 | | 4(7-3x)-(5-x)=23-11 | | 4(7-3x)-(5-x)=23-11x | | 12y=3.6 | | 2x+9=x+18=4x-3 | | 9x-6=30. | | 4x^2−371=29 | | 7n+2.5=58.5 | | 8x+5=4×+6 | | y=500+22,000 | | 2/3(x+6)+2=4 | | 4n-9=-25 | | 2(x-4)/3=4 | | 0.5x-77=180 | | 9y-21=6Y | | 6/10=2j/5 | | 5(x-6)-3x=2x-5 | | 1/2(x+2)=15 | | 3x-2=1.8 | | 2(x-4)/3=4* | | 5x+0.25=4 | | 3-2x+4=0.4x-0.5 | | x/5-3=1* | | x/3+1=5* | | 4(x-3)=12* | | 9(x-2)-2x=7x+5 | | g/2=-8 | | g=-3(-6) | | 120=340/4x | | 4n-9=72+7 | | 4n-9=72=7 |